Termination w.r.t. Q of the following Term Rewriting System could not be shown:
Q restricted rewrite system:
The TRS R consists of the following rules:
g1(f2(x, y)) -> f2(f2(g1(g1(x)), g1(g1(y))), f2(g1(g1(x)), g1(g1(y))))
Q is empty.
↳ QTRS
↳ Non-Overlap Check
Q restricted rewrite system:
The TRS R consists of the following rules:
g1(f2(x, y)) -> f2(f2(g1(g1(x)), g1(g1(y))), f2(g1(g1(x)), g1(g1(y))))
Q is empty.
The TRS is non-overlapping. Hence, we can switch to innermost.
↳ QTRS
↳ Non-Overlap Check
↳ QTRS
↳ DependencyPairsProof
Q restricted rewrite system:
The TRS R consists of the following rules:
g1(f2(x, y)) -> f2(f2(g1(g1(x)), g1(g1(y))), f2(g1(g1(x)), g1(g1(y))))
The set Q consists of the following terms:
g1(f2(x0, x1))
Q DP problem:
The TRS P consists of the following rules:
G1(f2(x, y)) -> G1(x)
G1(f2(x, y)) -> G1(g1(x))
G1(f2(x, y)) -> G1(y)
G1(f2(x, y)) -> G1(g1(y))
The TRS R consists of the following rules:
g1(f2(x, y)) -> f2(f2(g1(g1(x)), g1(g1(y))), f2(g1(g1(x)), g1(g1(y))))
The set Q consists of the following terms:
g1(f2(x0, x1))
We have to consider all minimal (P,Q,R)-chains.
↳ QTRS
↳ Non-Overlap Check
↳ QTRS
↳ DependencyPairsProof
↳ QDP
Q DP problem:
The TRS P consists of the following rules:
G1(f2(x, y)) -> G1(x)
G1(f2(x, y)) -> G1(g1(x))
G1(f2(x, y)) -> G1(y)
G1(f2(x, y)) -> G1(g1(y))
The TRS R consists of the following rules:
g1(f2(x, y)) -> f2(f2(g1(g1(x)), g1(g1(y))), f2(g1(g1(x)), g1(g1(y))))
The set Q consists of the following terms:
g1(f2(x0, x1))
We have to consider all minimal (P,Q,R)-chains.